Understanding the 'Remove Element' Problem
The 'Remove Element' problem asks us to remove all occurrences of a specific number, val
, from an array of numbers, nums
.
Problem Type- Easy
https://leetcode.com/problems/remove-element/description/
O(n) Solution
function removeElement(nums, val) {
let k = 0;
for(let i = 0; i < nums.length; i++) {
if(nums[i] !== val) {
nums[k] = nums[i];
k++;
}
}
return k;
}
Let me break it down for you:
I used two pointers,
i
andk
, to keep track of the array's elements.I checked if the current number is not equal to
val
.If it's not equal, I moved that number to the
k-th
position in the array.Finally, I returned
k
, which is the length of the new array without the specified number.It was easier for me as this problem was similar to Remove Duplicates , which also uses Two Pointers approach.
Comment if I have committed any mistake. Let's connect on my socials. I am always open for new opportunities , if I am free :P